Hi All,
I finally used white distilled vinegar (5%) today, in an attempt to derive 2% sodium acetate. The calculations I used were so generously provided by TopOfMurrayHill from this thread, although I read many other threads on the subject, too. So thank you, everyone, for all this knowledge! I just hope I got this right.
First, the numbers:
Oils: 567g
Water (33.33%): 157g
NaOH: 78g
2% sodium acetate desired
After doing the calculations, I came up with these revised numbers to use:
Vinegar: 99g
Water (actually aloe): 63g
NaOH: 81g
I wanted to use fresh aloe in place of additional water, so I slowly mixed the 81g NaOH into 99g vinegar. I did this outside with the container planted into a snow bank to avoid any overheating issues. It melted a fair bit of snow but otherwise did not appear to do anything dangerous. I left it outside after mixing for about 5 minutes, then brought it into the cold garage to continue to cool down. Since the vinegar is 5%, I took this to mean the other 95% is water and figured it should be enough to fully dissolve the NaOH. Or maybe not?
However, the lye never got 100% clear. There were bits floating in it that just never dissolved, but I can't say for certain it was lye beads. I'm familiar with the "crust" that can develop on top of lye solution as it reacts with air, and these bits were most certainly floating in the solution, not on top. I added 10g of distilled water to the lye thinking that might help, but it didn't, really. To be safe, I ended up filtering the solution just in case. Interestingly, I tried to filter it through a coffee filter but the liquid never penetrated the paper. It just sat on top, defiantly. So I used a fine mesh strainer, instead, which worked.
Is this normal when using vinegar?
I appreciate any insight!
-Angela
I finally used white distilled vinegar (5%) today, in an attempt to derive 2% sodium acetate. The calculations I used were so generously provided by TopOfMurrayHill from this thread, although I read many other threads on the subject, too. So thank you, everyone, for all this knowledge! I just hope I got this right.
First, the numbers:
Oils: 567g
Water (33.33%): 157g
NaOH: 78g
2% sodium acetate desired
After doing the calculations, I came up with these revised numbers to use:
Vinegar: 99g
Water (actually aloe): 63g
NaOH: 81g
I wanted to use fresh aloe in place of additional water, so I slowly mixed the 81g NaOH into 99g vinegar. I did this outside with the container planted into a snow bank to avoid any overheating issues. It melted a fair bit of snow but otherwise did not appear to do anything dangerous. I left it outside after mixing for about 5 minutes, then brought it into the cold garage to continue to cool down. Since the vinegar is 5%, I took this to mean the other 95% is water and figured it should be enough to fully dissolve the NaOH. Or maybe not?
However, the lye never got 100% clear. There were bits floating in it that just never dissolved, but I can't say for certain it was lye beads. I'm familiar with the "crust" that can develop on top of lye solution as it reacts with air, and these bits were most certainly floating in the solution, not on top. I added 10g of distilled water to the lye thinking that might help, but it didn't, really. To be safe, I ended up filtering the solution just in case. Interestingly, I tried to filter it through a coffee filter but the liquid never penetrated the paper. It just sat on top, defiantly. So I used a fine mesh strainer, instead, which worked.
Is this normal when using vinegar?
I appreciate any insight!
-Angela