Thank you. I know it is tough because I searched a whole lot of your threads and posts before I gave up and asked the question!!!!
How about if I just look up my notes and post them here?
Thank you. I know it is tough because I searched a whole lot of your threads and posts before I gave up and asked the question!!!!
How about if I just look up my notes and post them here?
Lovely! :mrgreen:
Done!! I've posted my notes (exactly as they were) from Evernote and an email message from TOMH. I hope this helps.
Hey, if my gallon of vinegar weighs 1000 grams, then I multiply that 1000 x .0337 to get the number of grams (33.7) of NaOH to pour into the jug, is that correct?
33.7 grams of NaOH will neutralize 1000 grams of 5% vinegar? Then I could just use this vinegar in place of my extra water?
"Question: I usually use dissolved salt and CA in my mixes and find that the CA makes a difference to soap scum for me.
Since the SA and CA take up "space" in the water you will not be able to dissolve as much salt in the liquid as you could in plain water. The same is true for sugar. The molecular bonding "space" is being occupied by SA and CA.
Thanks, Steve. I finally found TOMH's post regarding the .0335 calculation and was going to as you where you git your .0337 from; this explains it. I'm actually going to do this tonight. I've got an open bottle of vinegar at home. I'll pour all if that into the pitcher that I use when I do the vinegar lye solution and wait until it cools down before pouring back into the vinegar jug. FYI: It's actually safe to use the vinegar jug to make the solution because the jug is a #5 plastic. However, I like doing it in the pitcher because there is a larger surface area and wider mouth for the heat to disperse.Yes!
TopofMurrayHill's original calcs show a factor of .0335 so I am being just a tad "hot" with my lye using .0337. It amounts to .2 grams of lye per kilo of vinegar.
I would NOT just put the lye into the vinegar container since I am not sure of the material used is lye and heat safe. NEVER combine lye with anything in glass!!!
The reaction is exothermic ( releases heat) so I pour vinegar into one of my pitchers that is for soaping ( Dollar Store) and weigh the lye in it's own dry container, combine mix, wait for it to cool down some and funnel it into the jug that lives in the 'fridge.
If you know that you are going to use sodium citrate in your soap you could also react citric acid after mixing into the vinegar while it's still warm as well. I do not since I want more control over the amount of sodium citrate in each batch.
Question: I usually use dissolved salt and CA in my mixes and find that the CA makes a difference to soap scum for me. Will I still need to use CA with vinegar added to the mix?
Thanks all. This thread has been very useful. I want to make sure I understand what's going on. I am thinking of making a castile soap with 1600 g of olive oil with full water (38% of oil). I have attached a screenshot of the soapcalc recipe.
If I replace half my water with 5% vinegar I would need .0335*304 = 10.184 grams of extra NaOH to neutralize it.
But assume I calculate my recipe at 0% superfat and I decided NOT to add extra NaOH to neutralize the acetic acid. The NaOH needed to saponify this recipe is 216.76 grams so the amount removed in the acetic acid reaction would amount to 10.184/216.76 or about 4.7% of the total NaOH.
Is that 4.7% the same thing as saying the resulting soap would be 4.7% superfatted?
EDIT: Also, how do any of these calculations change if I decide to replace 5% of my NaOH with KOH?
Again, thanks for all your help.
Scooter
Time to trace really does not matter to me. I got interested in the dual lye trick based on some things I read from Earlene, concerning slime reduction: http://www.soapmakingforum.com/showthread.php?t=62022&highlight=dual+castileHowever, I'm really confused at what you are trying to do. The purpose of the vinegar/acetic acid is to harden the soap and cause a quicker trace (at least for me, I don' t know why anyone else uses it). By using 100% olive oil and "full" water, IMO, you are defeating the purpose of the vinegar/acetic acid.
FYI: Doing the old complicated math, which I've actually gotten used to, your half water amount (304 g vinegar) will be 288.8 water and 15.2 acetic acid. That ends up being slightly higher than the 2% sodium acetate I normally go for in my recipe. I would have had to throw in an additional 9.4 grams of NaOH to get my 2% (280.32 gr vinegar needed to make 2% sodium acetate). Having a real life situation to apply this to, I can see how much easier it is to have the neutralized vinegar on hand to use and not have to worry about "extra" anything.
Thanks all. This thread has been very useful. I want to make sure I understand what's going on. I am thinking of making a castile soap with 1600 g of olive oil with full water (38% of oil). I have attached a screenshot of the soapcalc recipe.
If I replace half my water with 5% vinegar I would need .0335*304 = 10.184 grams of extra NaOH to neutralize it.
But assume I calculate my recipe at 0% superfat and I decided NOT to add extra NaOH to neutralize the acetic acid. The NaOH needed to saponify this recipe is 216.76 grams so the amount removed in the acetic acid reaction would amount to 10.184/216.76 or about 4.7% of the total NaOH.
Is that 4.7% the same thing as saying the resulting soap would be 4.7% superfatted?
EDIT: Also, how do any of these calculations change if I decide to replace 5% of my NaOH with KOH?
Again, thanks for all your help.
Scooter
Our NaOH factor comes from calculating those proportions. 40 / 60 = .667 for the weight of tangerines needed for a given weight of grapefruit in order to have an equal number. That would be the number if our vinegar was actually 100% acetic acid in disguise. Since it's only 5%, the complete calculation is 40 / 60 * .05 = .0333.
Potassium hydroxide is a little chunkier, like an orange instead of a tangerine, so for KOH it would be 56 / 60 * .05 = .0467.
Thank you for this information, TeresaT...
Back to the castile being soft. I intend to cure it for a year, at least, so I'm assuming it will be plenty hard... again, I am more concerned with lather quality and slime reduction when it comes to the KOH.
Thanks again!
Scooter
I agree that others have said 5% KOH reduces snot in 100% Castile so go for it.
However, Teresa is right in that using full water for Castile is a bit strange. When you cure full water Castile for a year if it is 1 inch thick it will bend as it cures and it takes a long time to trace. There are no colours or additives to 100% Castile so it is just a matter of mix and pour into the mold. There does not seem to be any logic behind using full water.
I would use 30% Lye concentration minimum for castile and even up to 33% lye concentration with vinegar for a first attempt would still be forgiving.
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