"...counting the beer as half subsitution for water ?..."
Yes, that would work.
The only caution to keep in mind --NaOH needs water at least equal to the its weight to dissolve properly. In other words, you need at least 100 g of water to dissolve 100 g of lye. You can use more water than that, but you can't use less because the lye won't dissolve completely if there's not enough water. Maybe you know this already, and if so, I beg pardon -- I want to include this caution for other soapers who might not be aware of this.
I simmer my beer to about 1/2 its original volume. So if I were to make this recipe and I needed, say, a total of 400 g of "water", I would use 200 g of water to dissolve the lye, 100 g of concentrated dark beer for one half of the batch, and another 100 g of concentrated light beer for the other half. That will get "full beer" into the soap. :grin:
Yes, that would work.
The only caution to keep in mind --NaOH needs water at least equal to the its weight to dissolve properly. In other words, you need at least 100 g of water to dissolve 100 g of lye. You can use more water than that, but you can't use less because the lye won't dissolve completely if there's not enough water. Maybe you know this already, and if so, I beg pardon -- I want to include this caution for other soapers who might not be aware of this.
I simmer my beer to about 1/2 its original volume. So if I were to make this recipe and I needed, say, a total of 400 g of "water", I would use 200 g of water to dissolve the lye, 100 g of concentrated dark beer for one half of the batch, and another 100 g of concentrated light beer for the other half. That will get "full beer" into the soap. :grin:
