"... I have a theory that it is undisolved salt particles (deeanna, feel free to prove me wrong)...."
I'm not absolutely positive on this issue, but that's really the only thing it can be -- undissolved salt. Remember -- we're not dealing with the solubility of salt in plain water. Once the NaOH is added into the mix, the solubility of these chemicals becomes more complicated.
From what I recall, the people who are using brine this concentrated to make brine soap are just using the NaOH-NaCl-water solution as a milky liquid. Or they are going to using less salt to get a clear solution, as hmlove is doing.
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Regarding Roy's last post:
The solubility table that Roy references shows how many grams of solute (solute means the chemical that is being dissolved, such as salt, NaOH, etc) per 100 g of solvent (the solvent is what is doing the dissolving -- water in this case). The amount of solute dissolved by a given amount of solvent is one way to talk about solutions of chemicals, but it is not the only common way.
Chemists and soapers can also talk about solubility in terms of solution concentration. If we soap with a 33% lye solution concentration, that is a mixture of 1 part NaOH and 2 parts water. When the NaOH and water are mixed together 1/3 of the final solution is NaOH. The other 2/3 is water.
Salt solutions can be described in terms of solution concentration too. Using Roy's reference, we know that 36 g of salt can be dissolved by 100 g of water. What is the finished solution concentration? Well the total solution weighs a total of 36 g of salt + 100 g of water = 136 grams total. The percent of salt in this SOLUTION is this: 36 g salt / 136 g solution * 100% = 26% solution concentration. That means about 1/4 of the finished solution is salt and the other 3/4 is water.
Remember I said earlier in this thread that a saturated salt solution is about 26% by weight? I was expressing the same information as Roy, but just in terms of salt concentration, not in terms of g solute / g solvent as in Roy's table.
It gets confusing, hey?
For those who are feeling intimidated by the math, just be careful and ask your local science geek for help
if you're not sure.
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"...Calculate minimum amount of water needed to dissolve lye = 13.4 * .77 = 10.3 oz ..."
Moving on, I am befuzzled about the number 0.77 in this calculation. Even the referenced solubility table doesn't support the use of that value. ???