"...DeeAnna - is there a formula behind the numbers? ... I'm not entirely sure why the switching between the two systems is so confusing to me...."
Because it
IS confusing, even to me, and I'm pretty comfortable with math.
I was rushed this morning and didn't think it all through before I sent off my reply. The conversion is not only affected by superfat, as I mentioned earlier, but also by the fats in your recipe. This morning, I used a recipe that was 60:40 lard and coconut oil to crunch the numbers. If I use a different recipe with a different overall saponification value, the conversion from "water as % of oils" to "NaOH solution concentration" is slightly different. Ugh.
But it can be done. The easiest route is to convert a recipe from "water as % of oils" to "NaOH solution concentration". So here's an example of how Jennee might convert one of her recipes:
1. Pick a recipe of any size and any blend of fats. Use ounces or grams, whichever works best for you. Just keep your units consistent -- don't use ounces for water and grams for NaOH for example. Use ounces and ounces or grams and grams. To keep the numbers simple, I'm going to choose 100 grams (100 ounces works too) of lard as my example recipe.
2. Figure out the NaOH required for your recipe and your desired superfat. You can get this value from SoapCalc or your favorite
soap recipe calculator. For my example, I'm choosing 0% superfat. According to my
soap recipe calculator, the lye required to saponify 100 g of lard at 0% superfat is 14 grams of NaOH.
3. Pick a "water as % of oils" number that you want to use. For my example, I'm choosing "full water" at 38%. Calculate the grams of water from the total oil in the recipe and this percentage. The math:
Remember -- if you want to do math with percents, you must first convert the percentage to a decimal number:
38% / 100% =
0.38
Calculate the water from the total oil weight multiplied by the "water as % of oils" decimal number:
100 grams of oil X 0.38 =
38 grams water
4. I now have numbers for my water (38 g), NaOH (14 g), and total fat (100 g). Calculate the NaOH solution concentration from the grams of NaOH and the grams of water. (Keep in mind the total amount of lye solution = NaOH weight + water weight). The math:
Figure the total amount of NaOH solution -- it's the sum of all ingredients in the solution (the NaOH plus the water):
14 g NaOH + 38 g water =
52 g
Figure the NaOH solution concentration by dividing the NaOH weight by the total weight of the solution:
14 g NaOH / 52 g solution =
0.269
Convert this fraction into a percentage:
0.269 X 100 =
26.9% NaOH solution concentration
Done!
It is possible to convert a recipe based on "NaOH solution concentration" back to a basis of "water as % of oils" but it requires more algebra than Jennee's route. If y'all want to go there, I will show you how, but I'll do it in another post. I don't want folks to give up by dosing y'all with too much math at one time.